x^2+21^2=(x+8)(x+8)

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Solution for x^2+21^2=(x+8)(x+8) equation: 



x^2+21^2=(x+8)(x+8)

We move all terms to the left:

x^2+21^2-((x+8)(x+8))=0

We add all the numbers together, and all the variables

x^2-((x+8)(x+8))+441=0

We multiply parentheses ..

x^2-((+x^2+8x+8x+64))+441=0



We calculate terms in parentheses: -((+x^2+8x+8x+64)), so:

(+x^2+8x+8x+64)

We get rid of parentheses

x^2+8x+8x+64

We add all the numbers together, and all the variables

x^2+16x+64

Back to the equation:

-(x^2+16x+64)



We get rid of parentheses

x^2-x^2-16x-64+441=0

We add all the numbers together, and all the variables

-16x+377=0

We move all terms containing x to the left, all other terms to the right

-16x=-377

x=-377/-16

x=23+9/16

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